**Centripetal Acceleration** : In the case of an object moving to the right and speeding up So, right now, the acceleration and velocity vectors are parallel. Let’s now see if any other object is still moving to the right, but instead of accelerating, this object is slowing down.

The vectors for acceleration and velocity are negative if the boat is slowing down. When an object moves in a circle at a constant speed, does it experience acceleration since they are opposite.

Because the velocity changes based on the change in direction, even though this object is moving at a constant speed, there is an acceleration.

This acceleration points towards the centre of a circle, known as centripetal acceleration or centre acceleration.

In other words, if you want to say that an object is moving to the right, you should consider the centripetal acceleration, which is dependent on the speed and radius of the circle.

If you increase the speed of an object while it’s moving in a circle, the vector will be perpendicular to the velocity of the object between **V** squared dividing by **R**.

Taking the radius of the circle and reducing it to half, what happens is that 1 divided by 1/2 is 2, so if you reduce the radius to half, what will happen.

The radius of the centripetal is decreased. If you cut it, acceleration will increase. If you double it, it will be half Threefold the reduction.

The centripetal acceleration has tripled. Here’s a question for you: what’s going to happen to Reduce the radius to see what happens? A quarter of its value, and you increase.

By a factor of three, what would happen? Is this going to affect a centripetal motion Plug it in for acceleration to find out **9 /4 = 3**

**when multiplied by**

9×4 The elevation will rise by a factor of two 36 now there’s some other stuff you need to know these days how do you find the speed of the object if it’s moving in a circle as a constant speed whenever something is moving in a process at a constant speed it’s moving in uniform circular motion otherwise it’s not moving in uniform circular motion now to find the centripetal acceleration

## Newton’s second law

**We have a Newtonian formula for acceleration above, so the centripetal force must be: Newton’s second law states that force = mass * acceleration.**

**F** = **m v2** / **r**

*Here, m refers to mass.*

## With Incomplete Information Centripetal Force

You will likely not locate the centripetal force unless all of the records you want are available. If you think about it, however, you might typically be preparing what the force could be.

A planet orbiting another planet, or a moon orbiting a planet, generates centripetal force when gravitation is present.

Through the use of the normal equation for gravitational force, you could locate the centripetal force without the tangential pace:

**F = Gm1m2 / r2**

There are two masses, m1 and m2, which gravitate separately, and gravitational constant G.

## Centripetal Acceleration Formula

**a_c=** centripetal acceleration**v=** velocity**r =** radius

The formula for centripetal acceleration, often referred to as radial acceleration, is:**a_c = v^2 / r**

Where:

**a_c** is the centripetal acceleration, measured in meters per second squared **(m/s^2)**, v is the velocity of the object, measured in meters per second **(m/s)**, r is the radius of the path of the object’s motion, measured in meters (m)

This formula applies to any object moving in a circular path with a constant speed. It can calculate the centripetal acceleration at any point of motion.

This can be used in physics and engineering to calculate forces, motion, and motion planning of vehicles, among other applications.